Arizona AIMS Mathematics High School Sample Test Annotated Solutions Manual

This problem test to see if you can look at a situation and make some judgement calls.

The first judgement calls you need to make is the minimum and maximum possible distances Sean could have traveled.

If he drove for 6 hours at 55 MPH, then the minimum distance covered is 330 miles. This eliminates Choice A. This estimate is too low.

If he drove for 6 hours at 75 MPH, then the maximum distance covered is 450 miles. This eliminates Choice C because he was not driving 75 MPH during the entire journey. This also eliminates Choice D because that estimate is too high.

Only one choice remains. Choice B is the only reasonable distance Sean may have driven.

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this is a useless problem.
skip it.

i have never seen this in real life or in business on a daily basis.

IGNORE this ridiculous question. ^_^ …

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This question is checking if you remember your geometry objects. Choice B is not possible. A cone has a round base.

Choice C is not possible. A triangular pyramid has a triangular base.

Choice D is not possible. A square pyramid has a square base.

The only possible answer is Choice A.We see there is a downward (negative) slope that shows a trend of test scores as they are related to days absent.

It is safe to say that as students missed more days of school, their test score decreased.

Choice C is the correct answer.

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The first three terms of this series are:

(-7/4), (-10/4), (-13/4)

the next number is -4, we can also say that it is

(-16/4)

the next number is:

(-19/4)

The numerator adds -3 for each term. The denominator remains constant at 4.

It is safe to assume that Choice C is the correct answer.

Can you guess the next term?

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This graph depicts an object gaining height with distance then losing height with distance.

Choice B is the only choice that makes sense.

NOTE: This is NOT a correct illustration of projectile motion. If you think this question is a little strange, you are right.

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Algorithm I finds the median value of this data set of 25 values.

Algorithm II finds the median value of this data set of 25 values.

Algorithm III finds the maximum value.

Algorithm IV finds the mininum value.

Only I and II are equivalent. Your correct answer is Choice A.

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The first row of the table shows us the y-intercept is located at y = 4.

This fact eliminates Choices C and D.

The second row of the table shows us that the x-intercept is located at x = 2.

This eliminates Choice A.

The only possible answer is Choice B.

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The problem states that the first minute is $1.25. Thus, Choices A and C are eliminated.

The problem also says that for each additional minute, the caller will be charge $0.75.

If the total number of minutes on the phone is some time m. Then the additional minutes, excluding the first minute will be some shorter time (m - 1).

Your only answer is Choice B.

In fact, Choice D is overcharging you

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Method #1

Starting with the expression

2x(x² + 3xy + 6y²)

We multiply out the expression

2x³ + 6x²y + 12xy²

Choice B is the correct answer.

Another way to look at this is eliminating the impossible answers.

Choices C and D are not possible because the first x term is multiplied by an x² term yielding an x³ term as the first term of the expression.

Choice A is not possible because the last term must be an xy² term.

The only correct answer is Choice B.

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We start with

5x + (5/3)x ≤ -2x - (2/3)

Group like terms…

7x ≤ (-7/3)

Sovling for x

x ≤ (-1/3)

Choice B is the correct answer.

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